Transcript electric potential difference
Ch 25 – Electric Potential A difference in electrical potential
between the upper atmosphere and the ground can cause electrical discharge (motion of charge).
Ch 25 – Electric Potential So far, we’ve discussed electric
force
and
fields
.
Now, we associate a
potential energy function
with electric force.
This is identical to what we did with gravity last semester.
gravity
F g
G m
1
m
2
r
2
r
ˆ
g
G m r
2
r
ˆ
U g
G m
1
m
2
r
electricity
F e
k e
E
k e q
1
r
2
q
2
r q
2
r
ˆ ?
Ch 25.1 – Electric Potential and Potential Difference • Place a test charge,
q 0
, into an E-field. The charge will experience a force:
F
q
0
E
• This force is a conservative force.
• Pretend an
external agent
does
work
to move the charge through the E-field.
• The work done by the external agent
equals at least the negative of the work done by the E-field
.
Ch 25.1 – Electric Potential and Potential Difference • Let’s introduce a new symbol:
d s
• We’re talking about moving charges through some displacement.
• The “ ds ”
vector
is a little tiny step of displacement along a charge’s path.
Ch 25.1 – Electric Potential and Potential Difference • If
q 0
moves through the E-field by a little step some work: ds , the E-field does
dW
E field
F
d s
• As the E-field performs this work, we say that the
potential energy
of the charge-field system changes by this amount.
• This is the basis for our
definition of the potential energy function
.
Ch 25.1 – Electric Potential and Potential Difference • If
q 0
moves through the E-field by a little step some work: ds , the E-field does
dW
E field
F
d s
dU
dW
E field
F
d s
q
0
E
d s
U
U B
U A
q
0
A
B
E
d s
Ch 25.1 – Electric Potential and Potential Difference
U
U B
U A
q
0
A
B
E
d s
The change in electrical potential energy of a charge-field system as the charge moves from A to B in the field.
The integral accounts for the motion of the charge through a 1-D path. It’s called a “
path
” or “
line
”
integral
.
Ch 25.1 – Electric Potential and Potential Difference
U
U B
U A
q
0
A
B
E
d s
The change in electrical potential energy of a charge-field system as the charge moves from A to B in the field.
Because electric force is conservative, the value of the integral does not depend on the path taken between
A
and
B
.
Ch 25.1 – Electric Potential and Potential Difference
Potential Energy refresher:
Potential Energy measures the energy a system has
due to it’s configuration
.
U
U B
U A
q
0
A
B
E
d s
The change in electrical potential energy of a charge-field system as the charge moves from A to B in the field.
We always care about
changes
in potential energy – not the instantaneous value of the PE.
The zero-point for PE is relative. You get to choose what configuration of the system corresponds to PE = 0.
Ch 25.1 – Electric Potential and Potential Difference • What we’re about to do is different than anything you saw in gravitation.
• In electricity, we choose to divide
q 0
out of the equation.
V
U q
0
A
B
E
d s
• We call this new function, Δ
V
, the “
electric potential difference
.”
Ch 25.1 – Electric Potential and Potential Difference
V
U q
0
A
B
E
d s
Potential difference between two points in an Electric Field.
• This physical quantity only depends on the electric field.
• Potential Difference – the change in potential energy per unit charge between two points in an electric field.
• Units: Volts, [V] = [J/C]
Ch 25.1 – Electric Potential and Potential Difference
V
U q
0
A
B
E
d s
Potential difference between two points in an Electric Field.
• Do not confuse “
potential difference
” with a change in “
electric potential energy
.” • A potential difference can exist in an E-field regardless the presence of a test charge.
• A change in electric potential energy can only occur if a test charge actually moves through the E-field.
Ch 25.1 – Electric Potential and Potential Difference • Pretend an external agent moves a charge,
q
, from
A
to
B
without changing its speed. Then:
W
U
But:
V
U q
0
W
q
V
Ch 25.1 – Electric Potential and Potential Difference • Units of the potential difference are Volts: 1 V 1 J/C • 1 J of work must be done to move 1 C of charge through a potential difference of 1 V.
Ch 25.1 – Electric Potential and Potential Difference • We now redefine the units of the electric field in terms of volts.
1 N/C 1 V/m E-field units in terms of volts per meter
Ch 25.1 – Electric Potential and Potential Difference • Another useful unit (in atomic physics) is the electron-volt.
1 eV 1.60
10 -19 C V 1.60
10 -19 J The electron-volt • One electron-volt is the energy required to move one electron worth of charge through a potential difference of 1 volt.
• If a 1 volt potential difference accelerates an electron, the electron acquires 1 electron-volt worth of kinetic energy.
Quick Quiz 25.1
Points
A
and
B
are located in a region where there is an electric field.
How would you describe the potential difference between
A
and
B
? Is it negative, positive or zero?
Pretend you move a negative charge from
A
to
B
. How does the potential energy of the system change? Is it negative, positive or zero?
Ch 25.2 – Potential Difference in a Uniform E-Field Let’s calculate the potential difference between
A
and
B
separated by a distance
d
.
Assume the E-field is uniform, and the path,
s
, between
A
and
B
is parallel to the field.
V
A
B
E
d s
Ch 25.2 – Potential Difference in a Uniform E-Field Let’s calculate the potential difference between
A
and
B
separated by a distance
d
.
Assume the E-field is
uniform
, and the displacement,
s
, between
A B
is
parallel to the field
.
and
V
A
B
E
d s
V
A
B Eds
cos 1
V
E A
B ds
V
Ed
Ch 25.2 – Potential Difference in a Uniform E-Field
V
Ed
The negative sign tells you the potential at
B
is lower than the potential at
A
.
V B
<
V A
Electric field lines always point in the direction of decreasing electric potential.
Ch 25.2 – Potential Difference in a Uniform E-Field Now, pretend a charge
q 0
moves from
A
to
B
.
The change in the charge-field PE is:
U
q
0
V
q
0
Ed
If
q 0
is a positive charge, then Δ
U
is negative.
When a positive charge moves down field, the charge-field system loses potential energy.
Ch 25.2 – Potential Difference in a Uniform E-Field Electric fields accelerate charges… that’s what they do.
What we’re saying here is that as the E-field accelerates a positive charge, the charge-field system picks up kinetic energy.
At the same time, the charge-field system loses an equal amount of potential energy.
Why? Because in an isolated system without friction,
mechanical energy must always be conserved
.
Ch 25.2 – Potential Difference in a Uniform E-Field If
q 0
is negative then Δ from
A
to
B
.
U
is positive as it moves
U
q
0
V
q
0
Ed
When a negative charge moves down field, the charge-field system gains potential energy.
If a negative charge is released from rest in an electric field, it will accelerate against the field.
Ch 25.2 – Potential Difference in a Uniform E-Field Consider a more general case.
Assume the E-field is uniform, but the path,
s
, between
A
and
B
is
not
parallel to the field.
V
A
B
E
d s
Ch 25.2 – Potential Difference in a Uniform E-Field Consider a more general case.
Assume the E-field is uniform, but the path,
s
, between
A
and
B
is
not
parallel to the field.
V
B A
E
d s
E
B A
d s
E
s
U
q
0
V
q
0
E
s
Ch 25.2 – Potential Difference in a Uniform E-Field
V
E
s
If
s
is perpendicular to
E
(path
C
-
B),
the electric potential does not change.
Any surface oriented perpendicular to the electric field is thus called a
surface of equipotential
, or an
equipotential surface
.
Quick Quiz 25.2
The labeled points are on a series of equipotential surfaces associated with an electric field.
Rank (from greatest to least) the work done by the electric field on a positive charge that moves from
A
to
B
, from
B
to
C
, from
C
to
D
, and from
D
to
E
.
EG 25.1 – E-field between to plates of charge A battery has a specified potential difference Δ
V
between its terminals and establishes that potential difference between conductors attached to the terminals. This is what batteries do.
A 12-V battery is connected between two plates as shown. The separation distance is
d
= 0.30 cm, and we assume the E-field between the plates is uniform. Find the magnitude of the E-field between the plates.
EG 25.1 – Proton in a Uniform E-field A proton is released from rest at
A
in a uniform E-field of magnitude 8.0 x 10 4 V/m. The proton displaces through 0.50 m to point
B
, in the same direction as the E-field. Find the speed of the proton after completing the 0.50 m displacement.