Transcript Elliptic Curves and Elliptic Curve Cryptography

498-Elliptic Curves and Elliptic
Curve Cryptography
Michael Karls
1
Outline
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Groups, Abelian Groups, and Fields
Elliptic Curves Over the Real Numbers
Elliptic Curve Groups
Elliptic Curves Over a Finite Field
An Elliptic Curve Cryptography
Scheme—Diffie-Hellman Key
Exchange
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Group Definition

1.
2.
3.
4.
A group is a non-empty set G equipped with a
binary operation * that satisfies the following
axioms for all a, b, c in G:
Closure: a*b in G
Associativity: (a*b)*c = a*(b*c)
Identity: There exists an element e in G such that
a*e = a = e*a. We call e the identity element of G.
Inverse: For each a in G, there exists an element
d in G such that a*d = e = d*a. We call d the
inverse of a.
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Group Definition (cont.)
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5.
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If a group G also satisfies the
following axiom for all a, b in G:
Commutativity: a*b = b*a,
we say G is an abelian group.
The order of a group G, denoted |G| is
the number of elements in G. If |G| <
, we say G has finite order.
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Group Examples
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One example of a group is the set of real numbers with
addition.
The set of 2 x 2 matrices with real number entries and nonzero determinant forms a group under matrix multiplication.
Another group can be made from the set of permutations on
the set T = {1, 2, … , n}. This group is denoted by Sn.
Recall that a permutation is a 1-1 onto function from T → T.
When n = 3, the set of permutations on T is S3 = {(1) , (12), (13), (23),
(123), (132)}.
Recall that in cycle notation, for  = (12), (1) = 2, (2) = 1, and (3)
= 3.
For permutations  and , define the product   to be the
permutation obtained by applying  first, then .
For example, with  = (13) and  = (12),
  = (13)(12) = (132) and   = (12)(13) = (123).
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Group Examples
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
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Here is the “multiplication”
table for S3:
From the table, we see that
S3 is closed under this
product, the identity
element is (1), each
element has an inverse,
and the product is
associative.
Therefore, S3 is a group!
We call Sn the Symmetric
Group on n elements.
Which of these examples
are finite?
Which are abelian?
(1)
(12)
(13)
(23)
(123)
(132)
(1)
(1)
(12)
(13)
(23)
(123)
(132)
(12)
(12)
(1)
(123)
(132)
(13)
(23)
(13)
(13)
(132)
(1)
(123)
(23)
(12)
(23)
(23)
(123)
(132)
(1)
(12)
(13)
(123)
(123)
(23)
(12)
(13)
(132)
(1)
(132)
(132)
(13)
(23)
(12)
(1)
(123)
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Field Definition
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1.
2.
3.
4.
5.
A field F is a non-empty set with two binary
operations, usually denoted + and *, which satisfy
the following axioms for all a, b, c in F:
a+b is in F
(a+b)+c = a+(b+c)
a+b = b+a
There exists 0F in F such that a+0F = a = 0F+a. We
call 0F the additive identity.
For each a in F, there exists an element x in F
such that a+x = 0F = x+a. We call x the additive
inverse of a and write x = -a.
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Field Definition (cont.)
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6.
7.
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11.
Field axioms (cont.): For all a, b, c in F,
a*b in F
(a*b)*c = a*(b*c)
a*b = b*a
There exists 1F in F, 1F  0F, such that for each a
in F, a*1F = a = 1F*a. We call 1F the multiplicative
identity.
For each a  0F in F, there exists an element y in F
such that a*y = 1F = y*a. We call y the
multiplicative inverse of a and write y = a-1.
a*(b+c) = a*b + a*c and (b+c)*a = b*a + c*a.
(Distributive Law)
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Field Examples
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
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Note that any field is an abelian group under
+ and the non-zero elements of a field form
an abelian group under *.
Some examples of fields:
Real numbers
Zp, the set of integers modulo p, where p is a prime
number is a finite field.
For example,
Z7 = {0, 1, 2, 3, 4, 5, 6} and Z23 = {0, 1, 2, 3, … , 22}.
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Elliptic Curves Over the Real
Numbers
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Let a and b be real numbers. An elliptic curve E over the field
of real numbers R is the set of points (x,y) with x and y in R
that satisfy the equation
together with a single element , called the point at infinity.
There are other types of elliptic curves, but we’ll only consider
elliptic curves of this form.
If the cubic polynomial x3+ax+b has no repeated roots, we say
the elliptic curve is non-singular.
A necessary and sufficient condition for the cubic polynomial
x3+ax+b to have distinct roots is 4a3 + 27 b2  0.
In what follows, we’ll always assume the elliptic curves are
non-singular.
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Examples of Elliptic Curves
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y2 = x3-7x+6
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y2 = x3-2x+4
4
4
3
2
2
1
-3
-2
-1
1
2
3
4
-2
-1
1
2
3
4
-1
-2
-2
-4
-3
-4
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An Elliptic Curve Lemma
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The next result provides a way to turn the
set of points on a non-singular elliptic curve
into an abelian group!
Elliptic Curve Lemma: Any line containing
two points of a non-singular elliptic curve
contains a unique third point of the curve,
where
Any vertical line contains , the point at infinity.
Any tangent line contains the point of tangency
twice.
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Geometric Elliptic Curve
Addition
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Using the Elliptic Curve Lemma, we can
define a way to geometrically “add” points P
and Q on a non-singular elliptic curve E!
First, define the point at infinity to be the
additive identity, i.e. for all P in E,
P +  = P =  + P.
Next, define the negative of the point at
infinity to be -  = .
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Geometric Elliptic Curve
Addition (cont.)
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For P = (xP,yP), define the negative of
P to be -P = (xP,-yP), the reflection of
P about the x-axis.
From the elliptic curve equation,
we see that whenever P is in E, -P is
also in E.
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Geometric Elliptic Curve
Addition (cont.)
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1.
2.
3.
In what follows, assume that neither P
nor Q is the point at infinity.
For P = (xP,yP) and Q = (xQ,yQ) in E,
there are three cases to consider:
P and Q are distinct points with xP 
xQ.
Q = -P, so xP = xQ and yP = - yQ.
Q = P, so xP = xQ and yP = yQ.
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Geometric Case 1: xP  xQ
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By the Elliptic Curve
Lemma, the line L
through P and Q will
intersect the curve at
one other point.
Call this third point -R.
Reflect the point -R
about the x-axis to
point R.
P+Q = R
y2 = x3-7x+6

4
R
2
Q
P
-3
-2
-1
1
2
3
4
-2
R
-4
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Geometric Case 2: xP = xQ and
yP = - y Q
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In this case, the line L
through P and Q = -P
is vertical.
By the Elliptic Curve
Lemma, L will also
intersect the curve at
.
P+Q = P+(-P) = 
It follows that the
additive inverse of P
is -P.

y2 = x3-2x+4
4
3
P
2
1
-2
-1
1
2
3
4
-1
Q
-2
-3
-4
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Geometric Case 3: xP=xQ and
yP = y Q
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Since P = Q, the line L
through P and Q is tangent
to the curve at P.
If yP = 0, then P = -P, so
we are in Case 2, and
P+P = .
For yP  0, the Elliptic
Curve Lemma says that L
will intersect the curve at
another point, -R.
As in Case 1, reflect -R
about the x-axis to point R.
P+P = R
Notation: 2P = P+P
y2 = x3-7x+6

4
R
2
-3
-2
-1
1
2
3
4
-2
R
P
-4
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Geometric Elliptic Curve
Model
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For an interactive illustration of how
geometric elliptic addition works, a
great resource is Certicom’s
Geometric Elliptic Curve Model.
For the elliptic curves y2 = x3-7x+6 and
y2 = x3-2x+4, try adding points P and Q
or doubling P (i.e. 2 P = P+P),
graphically.
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Algebraic Elliptic Curve
Addition
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Geometric elliptic curve addition is useful for
illustrating the idea of how to add points on
an elliptic curve.
Using algebra, we can make this definition
more rigorous!
As in the geometric definition, the point at
infinity is the identity, -  = , and for any
point P in E, -P is the reflection of P about
the x-axis.
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Algebraic Elliptic Curve
Addition (cont.)
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1.
2.
3.
In what follows, assume that neither P nor Q
is the point at infinity.
As in the geometric case, for P = (xP,yP) and
Q = (xQ,yQ) in E, there are three cases to
consider:
P and Q are distinct points with xP  xQ.
Q = -P, so xP = xQ and yP = - yQ.
Q = P, so xP = xQ and yP = yQ.
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Algebraic Case 1: xP  xQ
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First we consider the case where P = (xP,yP) and Q = (xQ,yQ)
with xP  xQ.
The equation of the line L though P and Q is y =  x+, where
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In order to find the points of intersection of L and E, substitute
 x +  for y in the equation for E to obtain the following:
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The roots of (2) are the x-coordinates of the three points of
intersection.
Expanding (2), we find:
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Algebraic Case 1: xP  xQ
(cont.)
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Since a cubic equation over the real numbers has either one
or three real roots, and we know that xP and xQ are real roots,
it follows that (3) must have a third real root, xR.
Writing the cubic on the left-hand side of (3) in factored form
we can expand and equate coefficients of like terms to find
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Algebraic Case 1: xP  xQ
(cont.)
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We still need to find the y-coordinate of the third point, -R =
(xR,-yR) on the curve E and line L.
To do this, we can use the fact that the slope of line L is
determined by the points P and -R, both of which are on L:
Thus, the sum of P and Q will be the point R = (xR, yR) with
where
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Algebraic Case 2: xP = xQ and
yP = - y Q
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In this case, the line L through P and
Q = -P is vertical, so L contains the
point at infinity.
As in the geometric case, we define
P+Q = P+(-P) = , which makes P
and -P additive inverses.
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Algebraic Case 3: xP=xQ and
yP = y Q
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Finally, we need to look at the case
when Q = P.
If yP = 0, then P = -P, so we are in
Case 2, and P+P = .
Therefore, we can assume that yP  0.
Since P = Q, the line L through P and
Q is the line tangent to the curve at
(xP,yP).
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Algebraic Case 3: xP=xQ and
yP = y Q
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The slope of L can be found by implicitly
differentiating the equation y2 = x3 + ax + b
and substituting in the coordinates of P:
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Arguing as in Case 1, we find that
P+P = 2P = R, with R = (xR,yR), where
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Elliptic Curve Groups
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From these definitions of addition on an
elliptic curve, it follows that:
1.
Addition is closed on the set E.
Addition is commutative.
 is the identity with respect to addition.
Every point P in E has an inverse with respect to
addition, namely -P.
2.
3.
4.
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The associative axiom also holds, but is
“hard” to prove.
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Elliptic Curves Over Finite
Fields
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Instead of choosing the field of real numbers, we
can create elliptic curves over other fields!
Let a and b be elements of Zp for p prime, p>3. An
elliptic curve E over Zp is the set of points (x,y) with
x and y in Zp that satisfy the equation
together with a single element , called the point at
infinity.
As in the real case, to get a non-singular elliptic
curve, we’ll require 4a3 + 27 b2 (mod p)  0 (mod p).
Elliptic curves over Zp will consist of a finite set of
points!
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Addition on Elliptic Curves
over Zp
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Just as in the real case, we can define
addition of points on an elliptic curve E
over Zp, for prime p>3.
This is done in the essentially the
same way as the real case, with
appropriate modifications.
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Addition on Elliptic Curves
over Zp (cont.)
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Suppose P and Q are points in E.
Define P +  =  + P = P for all P in E.
If Q = -P (mod p), then P+Q = .
Otherwise, P+Q = R = (xR,yR), where
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Elliptic Curves Over Z23 Model
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Again, Certicom provides a model for
an elliptic curve over a finite field:
Finite Geometric Elliptic Curve Model.
For the elliptic curves y2 = x3+16x+6
and y2 = x3+21x+4 over the field Z23,
try adding points P and Q or doubling
P (i.e. 2P =P+P).
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Cryptography on an Elliptic
Curve
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Using an elliptic curve over a finite
field, we can exchange information
securely!
For example, we can implement a
scheme invented by Whitfield Diffie
and Martin Hellman in 1976 for
exchanging a secret key.
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Diffie-Hellman Key Exchange
via Colors of Paint
1.
2.
3.
4.
5.
6.
Alice and Bob each have a three-gallon bucket that
holds paint.
Alice and Bob choose a public color of paint, such
as yellow.
Alice chooses a secret color, red.
Alice mixes one gallon of her secret color, red, with
one gallon of yellow and sends the mixture to Bob.
Bob chooses a secret color, purple.
Bob mixes one gallon of his secret color, purple,
with one gallon of yellow and sends the mixture to
Alice.
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Diffie-Hellman Key Exchange
via Colors of Paint (cont.)
7.
8.
9.
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Alice adds one gallon of her secret color, red to the
mixture from Bob. Alice ends up with a bucket of
one gallon each of yellow, purple, and red paint.
Bob adds one gallon of his secret color, purple, to
the mixture from Alice. Bob ends up with a bucket
one gallon each of yellow, red, and purple paint.
Both Alice and Bob will have a bucket of paint with
the same color—this common color is the key!
Note that even if eavesdropper Eve knows that the
common color is yellow, or intercepts the paint
mixtures from Alice or Bob, she will not be able to
figure out Alice’s or Bob’s secret color!
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Diffie-Hellman Key Exchange
via an Elliptic Curve
1.
2.
3.
4.
Alice and Bob publicly
agree on an elliptic curve E
over a finite field Zp.
Next Alice and Bob choose
a public base point B on
the elliptic curve E.
Alice chooses a random
integer 1<<|E|, computes
P =  B, and sends P to
Bob. Alice keeps her
choice of  secret.
Bob chooses a random
integer 1<<|E|, computes
Q =  B, and sends Q to
Alice. Bob keeps his
choice of  secret.
1.
2.
3.
4.
Alice and Bob choose E to
be the curve y2 = x3+x+6
over Z7.
Alice and Bob choose the
public base point to be
B=(2,4).
Alice chooses  = 4,
computes P = B = 4(2,4)
= (6,2), and sends P to
Bob. Alice keeps  secret.
Bob chooses  = 5,
computes Q = B = 5(2,4)
= (1,6), and sends Q to
Alice. Bob keeps  secret.
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Diffie-Hellman Key Exchange
via an Elliptic Curve (cont.)
5.
6.
7.

Alice computes
KA = Q = (B).
Bob computes
KB = P = (B).
The shared secret key
is K = KA = KB.
Even if Eve knows the
base point B, or P or
Q, she will not be able
to figure out  or , so
K remains secret!
5.
6.
7.
Alice computes
KA=Q = 4(1,6) =
(4,2).
Bob computes
KB = P = 5(6,2) =
(4,2).
The shared secret
key is K = (4,2).
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References
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Hungerford, Thomas W. Abstract Algebra: An
Introduction Second Edition. New York: Saunders
College Publishing, 1997.
Koblitz, Neal. Algebraic Aspects of Cryptography.
Berlin: Springer-Verlag, 1999.
“Online ECC Tutorial.” Certicom.
http://www.certicom.com/index.php/10-introduction
Stinson, Douglas R. Cryptography Theory and
Practice Second Edition. New York: Chapman &
Hall/CRC, 2002.
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