kinetic theory of gases
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Transcript kinetic theory of gases
Kinetic Theory of Gases
Physics 313
Professor Lee Carkner
Lecture 11
Exercise #10 Ideal Gas
8 kmol of ideal gas
Compressibility factors
Zm = SyiZi
yCO2 = 6/8 = 0.75
V = ZnRT/P = (0.48)(1.33) = 0.638 m3
Error from experimental V = 0.648 m3
Compressibility factors: 1.5%
Most of the deviation comes from CO2
Ideal Gas
At low pressure all gases approach an ideal state
The internal energy of an ideal gas depends only
on the temperature:
The first law can be written in terms of the heat
capacities:
dQ = CVdT +PdV
dQ = CPdT -VdP
Heat Capacities
Heat capacities defined as:
CV = (dQ/dT)V = (dU/dT)V
Heat capacities are a function of T only for
ideal gases:
Monatomic gas
Diatomic gas
g = cP/cV
Adiabatic Process
For adiabatic processes, no heat enters
of leaves system
For isothermal, isobaric and isochoric
processes, something remains constant
Adiabatic Relations
dQ = CVdT + PdV
VdP =CPdT
(dP/P) = -g (dV/V)
.
Can use with initial and final P and V of
adiabatic process
Adiabats
Plotted on a PV diagram adibats have a
steeper slope than isotherms
If different gases undergo the same adiabatic
process, what determines the final properties?
Ruchhardt’s Method
How can g be found experimentally?
Ruchhardt used a jar with a small
oscillating ball suspended in a tube
Finding g
Also related to PVg and Hooke’s law
Modern method uses a magnetically
suspended piston (very low friction)
Microscopic View
Classical thermodynamics deals with
macroscopic properties
The microscopic properties of a gas are
described by the kinetic theory of gases
Kinetic Theory of Gases
The macroscopic properties of a gas are
caused by the motion of atoms (or molecules)
Pressure is the momentum transferred by atoms
colliding with a container
Assumptions
Any sample has large
number of particles (N)
Atoms have no internal
structure
No forces except
collision
Atoms distributed
randomly in space
and velocity
direction
Atoms have speed
distribution
Particle Motions
The pressure a gas exerts is due to the
momentum change of particles striking the
container wall
We can rewrite this in similar form to the
ideal equation of state:
PV = (Nm/3) v2
Applications of Kinetic Theory
We then use the ideal gas law to find T:
PV = nRT
T = (N/3nR)mv2
We can also solve for the velocity:
For a given sample of gas v depends only on
the temperature
Kinetic Energy
Since kinetic energy = ½mv2, K.E. per
particle is:
where NA is Avogadro’s number and k
is the Boltzmann constant