Transcript Solution

8.2

Multiplying, Dividing, and Simplifying Radicals

1

Multiply square root radicals.

2

Simplify radicals by using the product rule.

3

Simplify radicals by using the quotient rule.

4

Simplify radicals involving variables.

5

Simplify other roots.

Multiply square root radicals.

Product Rule for Radicals

For nonnegative real numbers

a

and

b

,

a

b

 and

a

b

.

That is, the product of two square roots is the square root of the product, and the square root of a product is the product of the square roots. It is important to note that the radicands not be negative numbers in the product rule. Also, in general,

x y x

y

.

EXAMPLE 1

Using the Product Rule to Multiply Radicals

Find each product. Assume that

x

 0.

3 6   5 11 13 

x

Solution:

   13 

x

 15  66  13

x

10  10   100  10

Simplify radicals by using the product rule.

A square root radical is simplified when no perfect square factor remains under the radical sign.

This can be accomplished by using the

product rule

:

a

b

EXAMPLE 2

Using the Product Rule to Simplify Radicals

Simplify each radical.

60

Solution:

 4  15  2 15 500  100  5  10 5 17 It cannot be simplified further.

EXAMPLE 3

Multiplying and Simplifying Radicals

Find each product and simplify.

10  50

Solution:

  500  100  5  10 5 6  2    12  2 3  12 50  2  60 2  12 25  2

Simplify radicals by using the quotient rule.

The quotient rule for radicals is similar to the product rule.

EXAMPLE 4

Using the Quotient Rule to Simplify Radicals

Simplify each radical.

Solution:

4 49  4 49  2 7 48 3  48 3  16  4 5 36  5 36  6 5

EXAMPLE 5

Using the Quotient Rule to Divide Radicals

Simplify.

8 50 4 5

Solution:

4 50 5 50 5 10  2 10

EXAMPLE 6

Using Both the Product and Quotient Rules

Simplify.

Solution:

3 8  7 2  8 2  21 16  21 16  21 4

Simplify radicals involving variables.

Radicals can also involve variables.

The square root of a squared number is always nonnegative. The absolute value is used to express this.

The product and quotient rules apply when variables appear under the radical sign, as long as the variables represent only

nonnegative

real numbers

a

2 

a

.

x

 0,

x

x

.

EXAMPLE 7

Simplifying Radicals Involving Variables

Simplify each radical. Assume that all variables represent positive real numbers.

x

6 100

p

8

Solution:

x

3  100 

p

8

Since

10

p

4   2 

x

6 7

y

4  7

y

4 

y

2

7

Find cube, fourth, and other roots.

Finding the square root of a number is the inverse of squaring a number. In a similar way, there are inverses to finding the cube of a number or to finding the fourth or greater power of a number.

The

n

th root of

a

is written

n a

.

a

,

n

is the

index

or

order

of the radical.

Index Radicand Radical sign

n a

It can be helpful to complete and keep a list to refer to of third and fourth powers from 1-10.

Simplify other roots.

To simplify cube roots, look for factors that are

perfect cubes

. A p

erfect cube

is a number with a rational cube root.

perfect cube.

3 64  4 4 is a rational number, 64 is a

Properties of Radicals

For all real number for which the indicated roots exist,

n a

n b

n ab

and

n a n b

 n

a b

b

 0  .

EXAMPLE 9

Finding Cube Roots

Find each cube root.

3 64 3  27 3 512

Solution:

 4

  3  8

4 4 3

EXAMPLE 8

Simplifying Other Roots

Simplify each radical.

108

Solution:

3

27 

3

4  160 16 625  

4 4

16

4

625 

4

16 

4

10   2 5

EXAMPLE 10

Finding Other Roots

Find each root.

Solution:

4 81

 3

 4 81   3 4  81 5 243 5  243

Not a real number.

 3

  3

3 3

EXAMPLE 9

Simplifying Cube Roots Involving Variables

Simplify each radical.

3

z

9

Solution:

z

3 8x 6  3 8  3

x

6

 2

x

2 3 54t 5 a 15 64   3 3 27

t

3 3

a

15 64  2

t

2  3 27

t

3 

a

5 4  3 2

t

2  3

t

3 2

t

2

8.3

Adding and Subtracting Radicals

1

Add and subtract radicals.

2

Simplify radical sums and differences.

3

Simplify more complicated radical expressions.

Add and subtract radicals.

We add or subtract radicals by using the distributive property. For example, 8 3  6 3 3  14 3 .

Only

like radicals

the

same number

— those which are multiples of the

same root

— can be combined this way. The preceding of example shows like radicals. By contrast, examples of

unlike radicals

are 2 5 and 2 3 ,

Radicands are different

as well as 2 3 and 2 3 .

Indexes are different

5 + 5

EXAMPLE 1

Adding and Subtracting Like Radicals

Add or subtract, as indicated.

8 5  2 5 7  10

Solution:

  5  10 5 

  9 11

 11

It cannot be added by the distributive property.

Simplify radical sums and differences.

Sometimes, one or more radical expressions in a sum or difference must be simplified. Then, any like radicals that result can be added or subtracted.

EXAMPLE 2

Simplifying Radicals to Add or Subtract

Add or subtract, as indicated.

27  12 5 200  6 18 

Solution:

 3 3  2 3  5 3   5

 5  100  2  32 2 9 

2      2

3 27  3 2

  3 2

 

Simplify more complicated radical expressions.

When simplifying more complicated radical expressions, recall the rules for order of operations.

A sum or difference of radicals can be simplified only if the radicals are like radicals.

cannot be simplified further.    5 3

EXAMPLE 3

Simplifying Radical Expressions

Simplify each radical expression. Assume that all variables represent nonnegative real numbers.

7  6  3

r

 8

r

Solution:

 147  2 27  2 27  49  3  2 27  7 3  2 27  7 3    7 3  6 3  13 3  6 

r

 2 2

r

 

r

 2 2

r

 18

r

 2 2

r

 9  2

r

 2 2

r

 3 2

r

 2 2

r

 5 2

r

EXAMPLE 3

Simplifying Radical Expressions (cont’d)

Simplify each radical expression. Assume that all variables represent nonnegative real numbers.

y 72  18

y

2 3 81

x

4  3 5 24

x

4

Solution:

y

 

y

y

 

y

9  8    9    3 2    

y

2  3 2  2

y

2

y

2     3

2 

y

2

  6 2

y

 3 2

y

 3 2

y

 3

y

2 

3 27

x

3  3 3

x

  3

x

 3 3

x

    13

x

3 3

x

  3

x

 3 3

x

 10

x

 3 3

x

3 8

x

3  3 3

x

  3 3

x

8.4

Rationalizing the Denominator

1

Rationalize denominators with square roots.

2

Write radicals in simplified form.

3

Rationalize denominators with cube roots.

Rationalize denominators with square roots.

It is easier to work with a radical expression if the denominators do not contain any radicals.

1 2  1  2  2 2  2 2 This process of changing the denominator from a radical, or irrational number, to a rational number is called

rationalizing the denominator

.

The value of the radical expression is not changed; only the form is changed, because the expression has been multiplied by 1 in the form of

2 .

2

EXAMPLE 1

Rationalizing Denominators

Rationalize each denominator.

Solution:

18 24  18 2 6  6 6

 18 6

 18 6 12  3 6 2 16 8  16 2 2  2 2  16 2  16 2 4  4 2

Write radicals in simplified form.

Conditions for Simplified Form of a Radical 1.

The radicand contains no factor (except 1) that is a perfect square (in dealing with square roots), a perfect cube (in dealing with cube roots), and so on.

2.

The radicand has no fractions.

3.

No denominator contains a radical.

EXAMPLE 2

Simplifying a Radical

Simplify 5 18 .

Solution:

 5 18  5 18  18 1 8  5  18 18  5  18  3  5  18 2  3 10 18  10 6  5  9  18 2

EXAMPLE 3

Simplifying a Product of Radicals

Simplify

1 2

5 .

6

Solution:

 2 6  5 12  5 12  5 2 3  3 3  5  6 3  15 6

EXAMPLE 4

Simplifying Quotients Involving Radicals

Simplify. Assume that

p

and

q

are positive numbers.

5

q p

5 2

p q

2 7

Solution:

 5

p

q q q

 5

pq q

 5 2

p q

7 2  35 2

p q

2 7 

pq

7 35   5 2

p q

2  7 7 7

p

2

q

2 7 35

EXAMPLE 5

Rationalizing Denominators with Cube Roots

3 3 Rationalize each denominator.

Solution:

3 2 3 5 6   3 3 3 5 6  3 3 6 2 6 2 3 2 3  3 3 3 2 3 2  3  3 6 3 2  3  3 3 3 2  3 180 6  3 18 3 3 3 3 4x ,

x

 0  3 3 3 4

x

 3 3 4 2

x

2 4 2

x

2  3 3 4 3

x

3

x

2  3 4

x x

2  3 8  3 6

x

2 4

x

 3 6

x

2 2

x

8.5

More Simplifying and Operations with Radicals

1

Simplify products of radical expressions.

2

Use conjugates to rationalize denominators of radical expressions.

3

Write radical expressions with quotients in lowest terms.

EXAMPLE 1

Multiplying Radical Expressions

Find each product and simplify.

2  8  20   2  5 3    3  2 2    

Solution:

   4 

5 

 2 5

 2  2   2 2

 5 3  5 3

 2 2

EXAMPLE 1

Multiplying Radical Expressions (cont’d)

 Find each product and simplify.

2  5    10  2 

Solution:

 2  2  20  2 5 50  10  10

EXAMPLE 2

Using Special Products with Radicals

 Find each product. Assume that

x

≥ 0.

5  3 2   4 2  5 2   2 

x

2  

Solution:

   

   3 2  9 

   

 

 5 2   25   2 2 

   

2

x

x

Remember only like radicals can be combined!

Using a Special Product with Radicals.

Example 3 uses the rule for the product of the sum and difference of two terms, 

x

y



x

y

 

x

2 

y

2 .

EXAMPLE 3

Using a Special Product with Radicals

 Find each product. Assume that 3  2  3  2 

y

 0.

y

 4 

y

 4 

Solution:

   2  2 

16

2  2

  1

Use conjugates to rationalize denominators of radical expressions.

The results in the previous example do not contain radicals. The pairs being multiplied are called

conjugates

of each other. Conjugates can be used to rationalize the denominators in more complicated quotients, such as 4  2 3 .

Using Conjugates to Rationalize a Binomial Denominator

To rationalize a binomial denominator, where at least one of those terms is a square root radical, multiply numerator and denominator by the conjugate of the denominator.

EXAMPLE 4

Simplify by rationalizing each denominator. Assume that

t

 0.

2  3 5

Using Conjugates to Rationalize Denominators

5+3 2  5

Solution:

 2  3 5  2  2  5 5   2 2     5 2   5     1 5      5     5 2   3   5   2 2   5 5     2 5 2 2  5 2     1 

EXAMPLE 4

Using Conjugates to Rationalize Denominators (cont’d)

Simplify by rationalizing each denominator. Assume that

t

 0.

2  3 t

Solution:

 2  3

t

 2  2    2 2    

t

2  

t

 4 

t t t

EXAMPLE 5

Writing a Radical Quotient in Lowest Terms

 Write in lowest terms.

10

Solution:

 5

10

 3  3 2

8.7

Using Rational Numbers as Exponents

1 2

Define and use expressions of the form a 1/

n

.

Define and use expressions of the form a

m

/

n

.

3

Apply the rules for exponents using rational exponents.

4

Use rational exponents to simplify radicals.

Define and use expressions of the form a 1/n .

Now consider how an expression such as 5 1/2 should be defined, so that all the rules for exponents developed earlier still apply. We define 5 1/2 so that 5 1/2 · 5 1/2 = 5 1/2 + 1/2 = 5 1 = 5.

This agrees with the product rule for exponents from

Section 5.1.

By definition,  5.

Since both 5 1/2 · 5 1/2 and 5  5 equal 5, this would seem to suggest that 5 1/2

should equal

Similarly, then 5 1/3

should equal

3 5.

5.

Review the basic rules for exponents:

n

a

 

n

a mn a m a n

a

Slide 8.7-4

Define and use expressions of the form a 1/n .

a

1/n

If

a

is a nonnegative number and

n

is a positive integer, then

a

1/

n

n a

.

Notice that the denominator of the rational exponent is the index of the radical.

Slide 8.7-5

EXAMPLE 1

Using the Definition of a 1/n

Simplify.

Solution:

49 1/2  49 

7

1000 1/3  3 1000 

10

81 1/4  4 81 

3

Slide 8.7-6

Define and use expressions of the form a

m/n

.

Now we can define a more general exponential expression, such as 16 3/4 . By the power rule, (a

m

)

n

= a

mn

, so 16 3/ 4 

16 1/ 4

3 

 

3  2 3  8.

However, 16 3/4 can also be written as 16 3/ 4 

 

1/ 4   4096  1/ 4  4 4096  8.

Either way, the answer is the same. Taking the root first involves smaller numbers and is often easier. This example suggests the following definition for

a m/n

.

a

m/n

If

a

is a nonnegative number and

m

and

n

are integers with

n > 0

, then

a

m

m

.

Slide 8.7-8

EXAMPLE 2

Using the Definition of a m/n

Evaluate.

9 5/2 8 5/3 –27 2/3

Solution:

   5    5  3 5  2 5 

243

32

   27 1/ 3  2  

 

2  

9

Slide 8.7-9

Using the definition of a

m/n

.

Earlier,

a –n

was defined as

a

n

 1

a n

for nonzero numbers

a

and integers

n.

This same result applies to negative rational exponents.

a

m/n

If

a

is a positive number and

m a

  and

n

1

a

are integers, with

n

> 0, then .

A common mistake is to write 27 –4/3 as –27 3/4 .

This is incorrect.

The negative exponent does not indicate a negative number. Also, the negative exponent indicates to use the reciprocal of the

base

, not the reciprocal of the

exponent.

Slide 8.7-10

EXAMPLE 3

Using the Definition of am/n

Evaluate.

Solution:

36 –3/2  1 36 3 / 2  1  36 1/ 2  3  1 6 3 81 –3/4  1 81 3/ 4  1  81 1/ 4  3  1 3 3  1 216  1 27

Slide 8.7-11

Apply the rules for exponents using rational exponents.

All the rules for exponents given earlier still hold when the exponents are fractions.

Slide 8.7-13

EXAMPLE 4

Using the Rules for Exponents with Fractional Exponents

Simplify. Write each answer in exponential form with only positive exponents.

7 1/ 3 9 2 / 3 9  1/ 3  7 2 / 3 27  5 / 3 8 3 1/ 2  3 3  5 / 2  2

Solution:

 7  9  

27 8

5 / 3 5 / 3

3

1/ 2  4/ 2   5/ 2

 7

9

 

27

1/ 3   5  5  3 2 / 2  

3 2 3

5 5

Slide 8.7-14

EXAMPLE 5

Using Fractional Exponents with Variables

Simplify. Write each answer in exponential form with only positive exponents. Assume that all variables represent positive numbers.

a

2 / 3 1/ 3 2

b c

 6

Solution:

 6 

a

12 / 3

b

6 / 3 12

c

 4 2 12

a b c r

2 / 3

r

  1

r

1/ 3 

r

r

6 / 3 

r

2  

a

2 / 3

b

1/ 4   3 

   

3 3 

a

6 / 3

b

3/ 4 

a

2

b

3/ 4

Slide 8.7-15

Use rational exponents to simplify radicals.

Sometimes it is easier to simplify a radical by first writing it in exponential form.

Slide 8.7-17

EXAMPLE 6

Simplifying Radicals by Using Rational Exponents

Simplify each radical by first writing it in exponential form.

4 12 2

Solution:

   1/ 4  12 1/ 2  12  2 3   3    1/ 6 

x

1/ 2   0

Slide 8.7-18

8.6

Solving Equations with Radicals

1

Solve radical equations having square root radicals.

2

Identify equations with no solutions.

3

Solve equations by squaring a binomial.

4

Solve radical equations having cube root radicals.

Solving Equations with Radicals.

A

radical equation

is an equation having a variable in the radicand, such as

x

3

or

3

x

8

x

9

Solve radical equations having square root radicals.

To solve radical equations having square root radicals, we need a new property, called the

squaring property of equality.

Squaring Property of Equality

If each side of a given equation is squared, then all solutions of the original equation are

among

the solutions of the squared equation.

Be very careful with the squaring property: Using this property can give a new equation with

more

solutions than the original equation has. Because of this possibility, checking is an essential part of the process.

All proposed solutions from the squared equation must be checked in the original equation.

EXAMPLE 1

Using the Squaring Property of Equality

Solve.

9 4

Solution:

9 

x

2

 4

2

9 16 9 

x

 9

 16

 9

x

7   7

It is important to note that even though the algebraic work may be done perfectly, the answer produced may not make the original equation true.

EXAMPLE 2

Using the Squaring Property with a Radical on Each Side

Solve.

3

x

Solution:

2

x

3

x

 9 

x

2

3

x

4

x

3

x

 9

 3

x

 4

x

 3

x x

 9

EXAMPLE 3

Using the Squaring Property When One Side Is Negative

Solve.

x

  4

Solution:

2

x

 16

2

Check:

x

 

4 16   4 4

 

4

False

x

principal

or

nonnegative

square root of

x

Example 3, we might have seen immediately that there is no solution.

in

Solving a Radical Equation.

Step 1

Solving a Radical Equation Isolate a radical.

Arrange the terms so that a radical is isolated on one side of the equation.

Step 2

Square both sides.

Step 3

Combine like terms.

Step 4

Repeat Steps 1-3

if there is still a term with a radical.

Step 5

Solve the equation.

Find all proposed solutions.

Step 6

Check all proposed solutions

in the original equation.

EXAMPLE 4

Using the Squaring Property with a Quadratic Expression

Solve

x

x

2  4

x

 16.

Solution:

x

2 

x

2

x

2 

x

2 

x

2

4

x

 4

x

16  16

2  

x

2

0

 4

x

4

x

4

x

4

x

16

 4

x

 

1 6

4

  4

Since x must be a positive number the solution set is Ø.

EXAMPLE 5

Using the Squaring Property when One Side Has Two Terms

Solve 2

x

10

x

 9.

Solution:

4

x

2

 4

x

2

x

 1

  10

x

 1

2  9 

 

10 10

x

x

9 

9

 2

 10

x

 9 

2

x

4 

x

2 



14 1 2

x x

0 0 2

x

1 0

x

 

1 2

or

2

x

0

x

 4

Since 2x-1 must be positive the solution set is {4}.

EXAMPLE 6

Rewriting an Equation before Using the Squaring Property

Solve.

25

x

Solution:

x

25

x

25

x

6 25

x

6 2  25

x

x

 6

2 

x

 6

x

2 

12

x

3 6

 25

x

0 0

x

2

x

13

x

 4



x

36  9

0

x

 4 4

or

0

x

 9 9

The solution set is {4,9}.

Solve equations by squaring a binomial.

Errors often occur when both sides of an equation are squared. For instance, when both sides of 9

x

 2

x

 1 are squared, the + 1

entire

binomial 2

x

. It is incorrect to square the 2

x

+ 1 must be squared to get 4

x

2 and the 1 separately to get 4

x

2 + 4 + 1 .

x

EXAMPLE 7

Using the Squaring Property Twice

Solve.

x x

1

Solution:

x x

x

1

2  

4

2 16

 

2

4

x x x x

  4 4

 2

x

 16

4

2  

x

 4

 32 4

x

 4

x

 8 4

The solution set is {8}.

Solve radical equations having cube root radicals.

We can extend the concept of raising both sides of an equation to a power in order to solve radical equations with cube roots.

EXAMPLE 8

Solving Equations with Cube Root Radicals

Solve each equation.

3 7

x

 3 4

x

 2

Solution:

3 7

x

 3 4

x

 2

3 7

x

 4

x

 2 3

x

3

x

  2 3 2 3 3

x

2 26

x

 27 3   3 

3  26

x

 27

3

x

2 0 0   26

x

  

x x

2    27 27 

x

 1  0

x

  27 27 or 0

x

 1   27,1  1