Transcript Molecular Structure and Bonding Theories
Daniel L. Reger Scott R. Goode David W. Ball
http://academic.cengage.com/chemistry/reger
Chapter 10 Molecular Structure and Bonding Theories
VSEPR
Valence-Shell Electron-Pair Repulsion Model
(VSEPR) predicts shape from Lewis Structures.
•
VSEPR Rule 1
: A molecule has a shape that minimizes electrostatic repulsions between valence-shell electron pairs. • Minimum repulsion results when the electron pairs are as far apart as possible.
Steric Number •
Steric number
= (number of lone pairs on central atom) + (number of atoms bonded to central atom) • The steric number is determined from the Lewis structure.
• Steric number determines the
bonded-atom lone-pair arrangement
, the shape that maximizes the distances between the valence-shell electron pairs.
Geometric Arrangements
Geometric Arrangements
Steric Number = 2 • In the Lewis structure of BeCl 2 ,
Cl Be Cl
beryllium has two bonded atoms and no lone pairs, steric number = 2 .
• A linear geometry places the two pairs of electrons on the central beryllium atom as far apart as possible.
• • • Molecules with Multiple Bonds The Lewis structure of HCN (H-C N:) shows that the carbon atom is bonded to two atoms and has no lone pairs, steric number = 2 .
The bonded-atom lone-pair arrangement is linear . The number of bonded atoms, not the number of bonds, determines the steric number.
Steric Number = 3 • The Lewis structure of BF 3
F B F F
shows the boron atom has a steric number = 3 ; the bonded-atom lone-pair arrangement is trigonal planar .
Steric Number = 4 • The Lewis structure of CH 4
H H C H H
shows the carbon atom has a steric number = 4 tetrahedral .
; the bonded-atom lone pair arrangement is
Steric Number = 5 • The phosphorus atom in PF 5 has a steric number = 5; the bonded atom lone-pair arrangement is trigonal bipyramidal .
Steric Number = 6 • The sulfur atom in SF 6 has a steric number = 6 ; the bonded-atom lone-pair arrangement is octahedral .
Central Atoms with Lone Pairs • The Lewis structure of H 2 O is
H O H
• • Steric number = 4 , 2 bonded atoms and 2 lone pairs.
The bonded-atom lone-pair arrangement is tetrahedral .
Molecular Shape of H 2 O • •
Molecular shape
is the arrangement of the
atoms
in a species.
The bonded-atom lone pair arrangement of H 2 O is tetrahedral (top); the molecular shape is bent or V-shaped (bottom).
Molecular Shape of NH 3 • What is the electron pair geometry and molecular shape of NH 3 ?
• • Electron Pair Repulsions The measured bond angle in H 2 O (104.5
o ) is smaller than the predicted angle (109.5
o ) Explanation: repulsions vary
lone pair-lone pair > lone pair-bonding pair > bonding pair-bonding pair
Location of Lone Pair in SF 4
Two structures are possible:
• The favored structure for a trigonal bipyramid minimizes 90 o lone pair interactions – the one on the right.
Lone Pairs in Trigonal Bipyramids • Lone pairs always occupy the equatorial positions in a trigonal bipyramid so that lone pair-lone pair repulsions are oriented at 120 o .
Location of Lone Pairs in XeF 4 • The structure on right has no 90 o lone pair-lone pair interactions and is favored.
Test Your Skill
• What is the steric number, the bonded atom lone-pair arrangement, and the molecular shape of ClF 3 ?
Multiple Central Atoms • • The geometry of each central atom is determined separately.
The C H 3 carbon in C H 3 CN has tetrahedral geometry and the other carbon has linear geometry.
Shapes of Molecules • What are the bonded-atom lone-pair arrangements and the shapes about each central atom in NH 2 SH?
• Draw the Lewis structure.
H H N S H
• The bonded-atom lone-pair arrangements of both are tetrahedral, the nitrogen shape is trigonal pyramidal and sulfur is “V” shaped.
Overall Shape of C 2 H 4 • Ethylene, C 2 H 4 , could be planar (left) or nonplanar (right). The VSEPR model does not predict which is preferred.
Polarity of Molecules • The bond dipoles in CO 2 cancel because the linear shape orients the equal magnitude bond dipoles in exactly opposite directions.
• Polarity of Molecules The bond dipoles do not cancel in COSe; they are oriented in the same direction and are of unequal length. They do not cancel in OF 2 because the V-shape of the molecule does not orient them in opposite directions.
• Polarity of Molecules The bond dipoles in BCl 3 and CCl 4 cancel because of the regular shape and equal magnitude.
• Polarity of Molecules The bond dipoles in BCl 2 F and CHCl 3 not cancel because they are not of the do same magnitude.
Test Your Skill
• Are the following molecules polar or nonpolar: H 2 S, SiF 4 , CH 2 Cl 2 ?
Valence Bond Theory • Valence bond theory describes bonds as being formed by overlap of partially filled valence orbitals.
Test Your Skill
• Identify the orbitals that form the bond in HCl.
• Bonding in NH 3 The observed bond angles of 107.5
o in NH 3 90 o are not consistent with the angles of expected if the bonds formed from N 2
p
orbitals.
Hybrid Orbitals •
Hybrid orbitals
are orbitals obtained by mixing two or more atomic orbitals on the same central atom.
• Appropriate hybrid orbitals formed by mixing one
s
and x
p
atomic orbitals make bonds at either 180 o (x = 1), 120 o (x = 2), or 109.5
o (x = 3).
Analogy for Hybrid Orbitals
sp
Hybrid Orbitals
Shape of Hybrid Orbitals • For clarity, hybrid orbitals are pictured as elongated with the small lobe omitted.
Bonding in BeCl 2 • The bonds in BeCl 2 overlap of two
sp
arise from the hybrid orbitals on the beryllium atom with the 3
p
orbitals on the two chlorine atoms.
sp
2 Hybrid Orbitals
Bonding in BF 3 • The bonds in BF 3 of three
sp
2 arise from the overlap hybrid orbitals on the boron atom with 2
p
orbitals on the three fluorine atoms.
sp
3 Hybrid Orbitals
• Bonding in CH 4 The bonds in CH 4 of four
sp
3 arise from the overlap hybrid orbitals on the carbon atom with 1
s
orbitals on the four hydrogen atoms.
Lone Pairs and Hybrid Orbitals • Hybrid orbitals can hold lone pairs as well as make bonds.
Hybridization with
d
Orbitals • Hybrid orbitals of central atoms with steric numbers of 5 or 6 involve
d
orbitals.
Hybrid Orbitals
Steric Number
2 3 4 5 6
Electron pair geometry
linear trigonal planar tetrahedral trigonal bipyramid octahedral
Hybridization
sp sp sp sp sp
3 3 2 3
d d
2
Test Your Skill
• Identify the hybrid orbitals on the central atoms in SiH 4 and HCN.
Types of Bonds: Sigma Bonds • Sigma bonds shared pair of ( s ): the electrons is symmetric about the line joining the two nuclei of the bonded atoms.
• • Bonding in C 2 H 4 The C-C sigma bond in C 2 H 4 arises from overlap of
sp 2
hybrid orbitals and the four C-H sigma bonds from overlap
sp 2
hybrid orbitals on C with 1
s
orbitals on H.
The second C-C bond forms from sideways overlap of
p
orbitals.
Types of Bonds: Pi Bonds •
Pi bonds (
p
)
places electron density above and below the line joining the bonded atoms – they form by sideways overlap of
p
orbitals.
Bonding in C 2 H 4 • The double bond in C 2 H 4 is one sigma bond and one pi bond – each bond is of similar strength.
Proof of Pi Bonds: Shape of C 2 H 4 • C 2 H 4 is planar (
A
) because pi overlap is at a maximum. Rotation of one end by 90 o (
B
) reduces pi overlap to zero.
Triple Bonds • The triple bond in C 2 H 2 is one sigma bond and two pi bonds between the
sp
hybridized carbon atoms.
Sigma Bonds in Benzene • Each carbon atom in benzene, C 6 H 6 , forms three sigma bonds with
sp
2 hybrid orbitals.
Pi Bonds in Benzene • The remaining
p
orbital on each carbon atom (top) overlap to form three pi bonds.
Test Your Skill
• Describe the bonds made by the carbon atom in HCN.
Molecular Orbital Theory • •
Molecular orbital theory
is a model that combines atomic orbitals to form new
molecular orbitals
that are shared over the entire molecule.
• A
bonding molecular orbital
concentrates electron density between atoms in a molecule.
An
antibonding molecular orbital
electron density between atoms in a molecule.
reduces
Hydrogen Molecule • Addition of the 1
s
orbitals of two H atoms forms a sigma bonding molecular orbital and subtraction forms a sigma antibonding molecular orbital, indicated with a * symbol.
Molecular Orbital Diagram: H 2 • Bonding molecular orbitals are more stable and antibonding molecular orbitals are less stable than the atomic orbital that are combined.
Bond Order •
Bond order
= 1/2 [number of electrons in bonding orbital - number of electrons in antibonding orbitals] • Bond order in H 2 = 1/2 [2 - 0] = 1
Molecular Orbital Diagram: He 2 • Bond order in He 2 = 1/2 [2 - 2] = 0; the molecule does not form.
Sigma Molecular Orbitals from
p
Pi Molecular Orbitals from
p
MO Diagram Second-Period Diatomics
Molecular Orbital Diagram: N 2 • The electron configuration is ( s 2
s
) 2 ( s * 2
s
) 2 ( p 2
p
) 4 ( s 2
p
) 2 .
• • The bond order in N 2 is three and there are no unpaired electrons. Lewis theory (:N N:) predicts the same result.
Molecular Orbital Diagram: Be 2 • The electron configuration is ( s 2
s
) 2 ( s * 2
s
) 2 . • Bond order in Be 2 is zero and the molecule does not exist.
Molecular Orbital Diagram for O 2 • Draw the molecular orbital diagram of O 2 . What is the electron configuration, the bond order and how many unpaired electrons are present?
Test Your Skill
• Draw the molecular orbital diagram of B 2 . What is the electron configuration, the bond order and number of unpaired electrons?