Fernandes-TheSolutionoftheBoltzmannConstant
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Transcript Fernandes-TheSolutionoftheBoltzmannConstant
RECONSTRUCTION OF THE GAS EQUATION
THE SOLUTION OF
THE BOLTZMANN CONSTANT
5
8.61022581810 e k
2 107 137.036 e k
BY
FRANCIS VIREN FERNANDES
DECEMBER 15, 2012
PV nkT
If
n 1 particle
PV kT
EE
I2 F
P 2
R
A
V R1 R2 R3
k 2 10 137.036 e
7
T eV ea
My Discoveries
ETHER IN DYNAMIC PULSATE MOTION
PLANCK ETHER MASS
mPl
186 ETHER MASS
c
Planck Mass 2.176450474×10 -8 kg
G
or B 2 137.036 Plancklength
2
I have discovered this correspondence in
the dynamic living pulsations of ether
B 1.3806680311036
WAVE-PARTICLE DUALITY
• Particle:
• Wave:
q M R 10
2
7
λ 2R 1
• Field:
M
1.859222909 1 0 9
1.346611109 1 0 27 k g/m
R
1.380668038 1 0 36
ETHER TORUS[Ђ]
186ether velocity Boltzmannradius Planck ' sh
1.86 109 25812.8075 1.380668 1029 h
737 Aitheron x f = 186-ETHER [Ę]
ONE 186-PHOTON TORUS ◌
SOLID ANGLE=4π×10-7
TWIN MASS
The Fractal Structure of Light & Emanation of Matter
A pulsating ether sphere rolling in a spinning pulsating ether torus Ђ
737 Wave-Maker
The energy of 737 equals the Planck’s constant
times one second
7.37 x 10-51 x c2 = h x 1.0
1.86 x 10-9 x VRk =7.37 x 10-51 x c2/1.38x10-29 x 1.0
So, the imposed condition is 1 second for the wavemaker to exist.
Coulomb’s Constant
K = c2 x 10-7
Velocity squared = v1 x v2
25812.8076 3.48181876510 K
5
The Boltzmann Constant
Superconductivity of SQUID & resistance
The ratio of the velocity of 186-ether to the
electrical resistance of a photon, c/e
(2 10 ) 137.036
R
Qt
7
25812.8076m / s
c / e 1.8711574691027 m / s.C
c
25812.8076 Boltzm ann' k
e
The Coulomb constant
25812.8076 x 34181.8779 m2/s2
f 2.5218363141041
1.859222909109 kg
f
7.372496371051 kg
f 1.859222909109 4.6886558471032 kg
4.6886558471032 kg
length
34181.8779m
27
1.34661110910 kg / m eter
25812.8076m (2 10 )137.036
7
t
E=mc2
25812.8076 3.48181876510 c
12
2
Ohm’s Law V=IR is F=ma
• OHM’S LAW Rewritten as F = ma
•
•
V=IR
• FERNANDES LAW
•
•
•
c
I F
2
a 10 F I
e
m m
7
(2 107 ) 137.036
R
Qt
• Acceleration, a as volts equals current, I the root of force, F times
resistance, R.
•
• Resistance, R is current, I per photon mass about one 186-seed ether.
•
Voltage is acceleration
Consider 511 keV for an electron
eV
V
e
511000
24
3
.
1894
10
Volts
19
1.60217653 10
c 2 107 (2.998108 ) 2 107
24
m/s2
Acceleration
3
.
1894
10
15
r
2.81794032510
q M R10
2
(1.602176537 1 0
1 .8592229091 0
7
19 2
9
)
1 .3806680311 0
36
1 0
7
CURRENT
Momentum = mv = Ft
1.859222909 x 10-9 kg x v = 25 x 3.20435306 x 10-20 s
v = 4.3087263 x 10-10 m/s
One coulomb of ether in kg = 1.859222909 x 10-9 kg x 6.24150948 x 1018 = 1.160435741 x 1010kg
Current is the momentum of one coulomb of ether,
Ether Current I = 5 amps = 1.160435741 x 1010kg x 4.3087263 x 10-10 m/s per one coulomb
Energy of ether drift, E = F r where r = 9.6064088 x 10-12m and F = I2
E = 25 x 9.6064088 x 10-12 = 2.4016022 x 10-10 J
E = m (cv) = 1.859222909 x 10-9 (2.99792458 x 108 x 4.3087263 x 10-10) = 2.4016022 x 10-10 J
Copper Current I = 5 amps = 2.672142823 x 10-27 x 6.24150948 x 1018 x 2.99792458 x 108 per
one Coulomb
The drift velocity of changed mass 2.672142823 x 10-27 kg of copper atoms
v = 7.34295219 x 10-4 m/s
E = m (cv) = 2.672142823 x 10-27 x (2.99792458 x 108 x 7.34295219 x 10-4) = 5.88235283 x 10-22 J
E = FR = 25 x 2.352941132 x10-23= 5.88235283 x 10-22 J
Remarks
The drift of ether and atoms of the conductor can be calculated by E = m (cv)
The mass of copper atoms changed under eVe stress from 1.05520602 x 10-25 kg to 2.672142823
x 10-27 kg
Maxwell thought that drift velocity was that of electrons. This has now been shown to be a false assumption.
NEWTON’S GRAVITATION CONSTANT DECONTRUCTED
G
G
B 2
c
36
1.380668031
10
2
c
1.859222909109
or
Ether 1.346611109 1027 6.371 106 8.579261033 kg
Force, F of earth mass, m oscillators F = m a
F 8.57926 1033 9.82
c2
F m
r
F 8.42483332 1034 N
c2
F 8.42483332 10 m
6.371106
m 5.9748 1024 kg
34
Force of entrained ether F = m a
Entrained Ether for Earth
The acceleration of entrained ether produces an acceleration of 9.8 m/s2
Radius of Earth 6.371 × 106 m
Magnetism
• MAGNETISM IDENTIFIED
The effect of magnetic flux [LHS] is caused by
current [RHS]
Ф = I x π x r x 10-7 x 137.036
UNIFICATION OF GRAVITY WITH ELECTROMAGNETISM
GEM
This is the unification of gravity with electromagnetism which is being searched
for because no one cared about the units of eV
MASS
Mass is an attribute of an oscillator measured differently by eV, R=I/m and F=ma.
These experimental mass measures differ by a rotational factor of
2 Pi x 10-7 x 137.036
Francis V. Fernandes (Born 1961)
Idiocy of energy units - It's too bad, but I have already apologized,
and there is nothing else I can do...
Richard P. Feynman (1961)
You Feynman recognized the error which physicists and
engineers memorized as truth; so here is my solution…
T 2
T 2
q
T 2
I
q I T
ml
mg
2
q
2
I
Q=Ixt
This formula Q = I x t represents a physical
reality when squared
q I t
2
2
2
m r 107 F t 2
r 10
F m 2
t
F m a
7
PV=kT
2
I
7
R1 R2 R3 2 10 137.036 e eV
2
R
2
R R1 R3
h
I
BA R1 R3
2e
R
2
F
I
P
A R1 R3
METHOD
• CV = velocity squared
• E = PV = kT = eVe = eae = hf = mc2
• m x r = e2
• Ф = I x π x r x 10-7 x 137.036
I know the formulas for volts, current and resistance
a = I x I/m
Time period of a pendulum
Particle volume of gas at 300kelvin
•
•
•
•
•
Vol = R1 x R2 x R3
Vol = 4.084572793 x 10-26 m3
R1 = 0.278731462 m
R2 = 0.557462906 m
R3 = 2.628722405 x 10-25 m
kT
ea T eV
5
8.61022581810 e k
2 10 137.036 e k
7
Energy, E=kT=PV
ea T eV
2 10 137.036 e k
7
2 10 137.036 e eV kT
7
2 10 137.036 e ea kT
7
2 10 137.036 E kT
7
E = eae = eVe
• At a temperature of say for example 300kelvin
and so
acceleration,a or volt,V=1.612224182x1017 m/s2
• E = kT = eae = 4.138530517x10-21 Joules
2 10 137.036 e eV kT
7
2 10 137.036 e ea k 300
7
Speed of hydrogen molecule mass, m
at 300K is 1927m/s
acceleration, a =1.612224182x1017 m/s2
2
2
v
v
a
r 3r
v 1927 m / s
q m r 10
2
7
r 7.6734889951012 m
angle x alpha-1 x e x ea
2 107 137.036 e eV kT
2 10 137.036 e ea k 300
7
Boltzmann, k e precession
T x e = ea x e = 300 x e = E = m(cv)2
19
E 3001.6021765310 J
17
E 4.8065295910 J
17
E 4.8065295910
17
E 4.8065295910
(2 10 )137.036
21
E 4.13853051710
J
7
J PV kT
R2 = 0.557462906 m
E 4.1385305171021 J PV kT
E m c2 hf
f 6.2458304161012 Hz
1
t 1.6010681261013 s
f
m 4.6047362121038 kg
I
c
2.99792458108
27
R
1
.
871157469
10
ohm s
19
m q 1.6021765310
I m R 4.6047362121038 kg 1.8711574691027 ohm s
I 8.6161865541011 Am p
R2 = 0.557462906 m
38
m 4.60473621210 kg
q m R2 10
2
7
R2 0.557462906m
R1 = 0.278731462 m
38
m 4.60473621210 kg
q m R2 10
2
7
R2 0.557462906
m
q 2m R3 10
2
7
R2
R1
0.278731453
m
2
R3 = 2.628722405 x 10-25 m
Ro = 3.053023765 x 10-21 m
Volume = 4.084572793 x 10-26 m3
Volum e
Area
R2
26
4.08457279310
7.32707641026 m 2
Area, A
0.557462906
2.067837171015
MagneticField , B
A 7.32707641026
B 2.8221811871010 Am p/ m eter
DONE AWAY WITH SIN COS i j k
R3
&
Ro
I
B
R
8.6161862341011
21
R
3
.
053023765
10
m
10
2.82218118710
R3 R 2 107 137.036 2.6287224051025 m
Drift velocity E/B = v
F I 2 (8.6161862341011 ) 2
Electricfield , E
q
q
1.602176531019
E 0.046336133N / C
E
0.046336133
12
v
1
.
641855357
10
m/s
10
B 2.82218118710
R3 2.62872240410 25
12
v
1
.
641855434
10
m/s
13
t
1.60106812710
Drift velocity squared cv
q m R3
2
14
m 9.76508447310 kg
Energy, E e 300kelvin eea
E m cv 4.8065294131017 J
Squid Velocity of 186-ether propels hydrogen
gas molecules – the reason for Brownian motion
186ether velocity Boltzmannradius Planck ' sh
9
1.86 10 25812.8075 1.380668 10
29
h
v
25812.8076
17
2
a
1
.
612224182
10
m
/
s
t 1.6010681271013
v2 v2
a
r 3r
v 1927 m / s
q m r 10
2
7
12
r 7.67348899510 m
VELOCITY SQUARED OF LIGHT SPEED C2
25812.8076 X 3.481818765 X 1012
m 4.604736212
1038 kg
q 2 m r 107
R2 0.557462906
m
v2
0.557462906
12
3
.
481818761
10
m / s[ FTL]
13
1.601068132
10
v1 25812.8076
t
1.601068132
1013
4.132806365 109 m
mc h
m 5.347985402
1034 kg
E m c2 4.806529576
1017 J
E eT eea e 300J
T x e = ea x e
17
E
4.8065295910
a 2
19 2
e
(1.6021765310 )
a 1.87245284410 m / s
T ea eV 300kelvin
21
2
Analysis of Volume = R1 x R2 x R3
AT 300 KELVIN
A = R1x R3
R1 = 0.278731462 m
2m
Used to calibrate
voltmeters
B A is the magnetic
flux quantum
Pressure = Current
squared per area A
R2 = 0.557462906 m
R3 = 2.6287224 X 10-25 m
m
m*
The photon mass
measured due to
737-frequency
The FTL component
velocity of speed of
light squared
Measured in
magnetism
The source of
magnetism
PV=kT
2
I
R1 R2 R3 2 107 137.036 e e a
R1 R3
F
V 2 107 137.036 E
A
Spectroscopy
The mass of a proton, m2 is changed
from 1.672622216 x 10^-27kg to
3.634114179 x 10^-29kg when
0.068amps of current is passing thru
water during electrolysis
The energy as measured for a proton E = F R = I^2 R
The radius of a proton q^2 = m R 10^7 and so
R = 1.5347 x 10^-11m
E = 0.068^2 x 1.5347 x 10^-11 = 7.0964528 x 10^-14 J
E = m1c^2 and so m1 = 7.895868606 x 10^-31kg
Originally before electricity was passed the energy of
the proton E = mc^2
E = 1.672622216 x 10^-27 x c^2 = 1.503275 x 10^-10 J
E = I^2 R
1.503275 x 10^-10 = 0.068^2 x R
R = 3.251029 x 10^-8 m
Q^2 = 7.895868606 x 10^-31 x 3.251029 x 10^-8
In any interaction its always
I1 x I2 or m1 x m2 or r1 x r2
So m1 x m2 = 7.895868606 x 10^31kg x 1.672622216 x 10^-27
Square root of these masses =
3.634114179 x 10^-29kg [ R = I /
m]
Q^2 = 3.634114179 x 10^-29 x
7.063536 x 10^-10
This is the oscillator that yields
the clock frequency
The radius of the proton changes
from R = 1.5347 x 10^-11m to
7.063536 x 10^-10m
I
1.871157469 10 27 amp / kg
m
0.068
m
m 3.63411424 10 29 kg
Transient mass
The Planck energy involves 2Pi x 137.036
E = m x 2Pi x 137.036 x c2 x 10-7 = 2.81225386 x
10-16 J
E=hf
f = 4.24422646 x 1017 Hz
t = 1/f = 2.35614196 x 10-18s
18000 / 2.35614196 x 10-18= 7.639607603 x 1021
Thus the time for hydrogen to evolve at the
cathode is inversely proportional to the frequency
of the changed mass of a proton under external
current stress during electrolysis of water.
Mass Length Time period
This experiment is conclusive evidence that …..
• Our measure of mass is at light speed. Mass is
already at light speed.
• The frequency of the oscillator changes drastically
on insults
• Frequency change means mass and radial length
change
• I am able to crack these issues because voltage is
acceleration, current squared force and
resistance always constant at 1.87 x 10^27
amp/kg or velocity / elementary charge
Magnetism
• h/2e = I x Pi x R x 137.036
• Ф = 0.068 x Pi x 7.0635359 x 10-17 x 137.0359991
I have deconstructed the magnetic flux quantum.
Gravitational force
F = mg = 0.008kg x 9.8 = 0.0784 N
F = I2 = 0.392 A x 0.2 A = 0.0784 N
• So, current of 0.392 A is required to flow thru a 0.50 m
conductor placed 90 degrees to the magnetic field, of
strength 0.40 T for a levitation effect.
• Let us consider current generated by the magnetic field, B
of 0.4 T on 0.5m length of the conductor.
•
I = 0.4 T x 0.5 m = 0.2 A
• F = I2 = 0.392 A x 0.2 A = 0.0784 N
The Rydberg Mass
13.6 eV the first ionization electron volt
energy of an electron for the hydrogen atom
corresponds to a Rydberg photon and not a
511 keV electron
13.60569223 x e = 2.179872077 x 10-18 J
E = mc2 and so m= 2.425434789 x 10-35 kg
The Reason for Spectra
2.425434789 x 10-35 x c x λ = h
inverse of lambda is the Rydberg number
Radius
Energy
R= 1.5347 x 10-11 m
E = F x R = I2 x R
E = mc2 where m is external photon
Resistance
I
m rydberg
c
1.8711574691027 m / sC
e
m rydberg m proton m externalphoton
Changed measured mass
1.
2.
3.
4.
Maxwell drift of changed copper mass
Electrolysis of water
Spectrum of Hydrogen
A magnetic field which contributes to gravitational
force of a rod. I have shown how a plane has lift in a
similar manner.
THERE IS ONE MASS [ 7.37x10-51kg x f ] MEASURED
DIFFERENTLY AS IT MOVES ALONG 4 PATHS NAMELY
R1 R2 R3 R0
Twin Mass –Ether & Matter
Point mass 737-wavemaker must exist
Twin Mass Structure
Ether Mass and associated charge
7.372496 x 10-51 kg Oscillator x frequency , f = Photon mass
c = f x λ
Photon mass x # = 1.859222909 x 10-9 kg
(Matter)
(Elementary charge / oxidation state)
1.859222909 x 10-9 kg Torus x # = Ether Mass
(186-ether)
etherm ass
radiusofphoton
27
1.34661110910 kg / m
STRUCTURE OF SPACE
1. Twin mass = Ether and Matter
2. Etheric sea = Ether and Ether
3. Void
= Soul
Entropy Units! ????
H
S
T m ol
eV e T e
S
m ol T m ol T
eVe
S
n e m ol1
eV m ol
Entropy
Slowing down of photon speed is my idea of generating
free energy from the structure of space
Entropy is the energy required to raise the energy of one
mole of substance from zero to 298 kelvin
I would redefine entropy as the energy input to slow down
speed of a photon from light speed c to drift velocity v
E = mc2 = m x 25812.8076 x 3.481818 x 1012
E = mxcxv