Transcript Section 9.2

Wednesday, Oct. 2nd: “A” Day
Thursday, Oct. 3rd: “B” Day
Agenda
Sec 9.2: “Limiting Reactants and Percentage
Yield”
Limiting/ Excess Reactants, Theoretical Yield,
Actual Yield, Percentage Yield
Homework:
Sec. 9.2 review, pg. 319: #1-10
Concept Review
Limiting Reactants and Theoretical Yield
In the previous section, we assumed that
100% of the reactants changed into products.
Theoretically, that is what SHOULD happen,
but in the real world, other factors like these
can limit the yield of a reaction:
Amounts of all reactants
Completeness of the reaction
Products lost in the process
S’More Activity
See how many s’mores you can make from the
marshmallows, graham crackers and chocolate
that you’re given.
Which ingredient did you run out of first?
Which ingredients do you have left over?
In this case, the chocolate is the limiting
reactant and the marshmallows and graham
crackers are the excess reactants.
The Limiting Reactant Forms the Least
Amount of Product
 Limiting Reactant: the substance that controls the
quantity of product that can form in a chemical
reaction.
This reactant is completely used
up in the reaction.
 Excess Reactant: the substance that is not used up
completely in the reaction.
There will be some of this reactant left over after
the reaction.
The Limiting Reactants are often the
More Expensive Reactants
In industry, the cheaper reactants are often
used as the excess reactants.
In this way, the more expensive reactants are
completely used up, saving the company
money.
Example
One way to make hydrogen gas, H2 is:
Zn + 2 HCl
ZnCl2 + H2
Question: If you combine 0.23 mol Zn and
0.60 mol HCl, would they react completely?
0.23 mol Zn
? Mol H2
0.23 mol H2
0.60 mol HCl
? Mol H2
0.30 mol H2
Example
Zn + 2 HCl
0.23 mol Zn
0.60 mol HCl
ZnCl2 + H2
0.23 mol H2
0.30 mol H2
Since 0.23 mol of Zn makes less H2 than 0.60
mol of HCl, Zn is the limiting reactant and will
be completely used up.
HCl is the excess reactant, meaning that there
will be some HCl left over.
Determine Theoretical Yield From
Limiting Reactant
Theoretical Yield: the maximum quantity of
product that a reaction could theoretically
make if everything about the reaction works
perfectly.
The theoretical yield is ALWAYS based on the
limiting reactant.
Sample Problem E, pg. 314
 Identify the limiting reactant and the
theoretical yield of phosphorous acid, H3PO3,
if 225 g of PCl3 is mixed with 123 g of H2O.
PCl3 + 3 H2O
H3PO3 + 3 HCl
1. Use stoichiometry to calculate the MASS of
H3PO3 you could form from each reactant.
2. The reactant that produces the least amount
of H3PO3 is the limiting reactant.
3. The theoretical yield is the amount of H3PO3
produced from the limiting reactant.
Practice
PCl3 + 3 H2O
H3PO3 + 3 HCl
Identify the limiting reactant and theoretical yield
(in grams of HCl) for these reactants:
3.00 mol PCl3 and 3.00 mol H2O
3.00 mol PCl3 X 3 mol HCl X 36.46 g HCl = 328 g HCl
1 mol PCl3 1 mol HCl
3.00 mol H2O X 3 mol HCl X 36.46 g HCl = 109 g HCl
3 mol H2O 1 mol HCl
H2O is the limiting reactant.
Theoretical yield is 109 g HCl.
Actual Yield
Actual yield: The measured amount of a
product of a reaction.
What you actually got from the experiment.
Theoretical yield = what you should get if
everything works perfectly
Actual yield = what you actually get
Actual Yield
The actual yield is usually less than the theoretical
yield. WHY?
1. Many reactions do not completely use up the
limiting reactant. Some of the products turn
back into reactants (reversible reaction).
2. The final product may need to go through
additional purification processes (filtering,
distilling, etc) and some product may be lost.
3. There could be other side reactions that use up
the limiting reactant without making the
desired product.
Percentage Yield
The percentage yield is found by simply
dividing the actual yield by the theoretical
yield and multiplying by 100%.
Percentage Yield = Actual Yield
X 100%
Theoretical Yield
The percentage yield describes the efficiency
of a reaction.
Sample Problem F, pg. 317
Determine the limiting reactant, the theoretical
yield, and the percentage yield if 14.0 g of N2 are
mixed with 9.0 g H2 and 16.1 g NH3 form.
N2 + 3 H2
2 NH3
1. Use stoichiometry to calculate the MASS of
NH3 you could form from each reactant.
2. The reactant that produces the least amount of
NH3 is the limiting reactant.
3. The theoretical yield is the amount of NH3
produced from the limiting reactant.
4. Use the theoretical yield and the actual yield
(16.1 g) to calculate the percentage yield.
Practice
Determine the limiting reactant and the percentage
yield for the following:
N2 + 3 H2
2 NH3
14.0 g N2 react with 3.15 g H2 to give an actual yield
of 14.5 g NH3.
N2 is the limiting reactant.
Theoretical yield = 17.0 g NH3.
Percentage yield = 85.3%
Homework
Sec. 9.2 review, pg. 319: #1-10
Concept Review
Quiz over section 9.2 next time…