chemistry - mathematical lesson (PPT
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Transcript chemistry - mathematical lesson (PPT
“When the well is
dry, we know the
worth of
water”
Benjamin Franklin
Mineral water
(integrated mathematic-chemistry lesson)
The aim of the lesson:
to get acquainted with variety
of mineral waters of Lithuania.
The goals of the lesson:
To explore general mineralization of mineral
water.
To measure qualitative components of mineral
water “Vytautas”.
To learn to solve integrated mathematicschemistry tasks.
The classification of mineral water
Mineral waters
wich have very few
minerals: the
concentration of
minerals ≤ 50mg/l.
Examples:
“Neptūnas”
“Rytas”
“Perrier”
“Vittel”
Mineral waters
wich have few
minerals: the
concentration of
minerals ≤ 500mg/l.
Mineral waters
wich have a lot of
minerals: the
concentration of
minerals > 1500mg/l.
Examples:
“Rasa”
“Vytautas”
“Naleczovanka”
“Augustovianka”
0
605
877
Naleczovianka
403
Augustovianka
2745
Fuldataler
349
Perrier
500
Vittel
4000
Vichy Celestines
Neptūnas
2000
Tiche
3000
ruskininkų Rasa
1000
Aqville
Birutė
8000
Vytautas
Total Dissolved Solids (TDS)
mg/l
7200
7000
6000
5000
3378
2515
2017
1378
713
Answers of group chemistry tasks:
Group 1 : Ag+(aq) + Cl-(aq) → AgCl(s)
Group 2 : Ca2+(aq) + CO32-(aq) → CaCO3(s)
Group 3 : Ba2+(aq) + SO42-(aq) → BaSO4(s)
Group 4 : H+(aq) + HCO3-(aq) → CO2(g) + H2O(l)
n
1. C =
V
534 mg/l · 1l = 534 mg
534
= 0,534 g
1000
n(Ca2+ )=
0,534g
= 0,013mol
40g / m ol
0,013 mol
2 0,013 mol / l
C=
2l
2. Ca2+(aq) + Na2CO3(aq) → CaCO3(s) + 2Na+(aq)
n(Ca2+) = 0,013 mol
n(Na2CO3) = 0,013 mol
n
C=
V
0,013m ol
V=
0,5m ol/ l
= 0,026l
3. “Vytautas”
3437mg/l · 1l = 3437mg
3437 mg
=
= 3,437g
1000
3,437g
w(Cl ) =
· 100% = 47,98%
7,165g
m(Cl-)
“Perrier”
21,5mg/l · 1l = 21,5mg
21,5mg
m(Cl ) =
1000
0,0215g
w(Cl ) =
· 100% = 3,56%
0,6046g
1.
Let us assume, that:
x is the number of small bottles (0,5l),
y is the number of large bottles (1,5l).
Make an equation system:
x + y = 36
0,5x + 1,5y = 42
x = 36 – y
0,5x + 1,5y = 42
0,5 · (36 – y) + 1,5y = 42
18 – 0,5y + 1,5y = 42
y = 42 – 18
y = 24
x = 36 – 24 = 12
The answer: there are 12 small bottles (0,5l) and 24 large
bottles (1,5l)
2.
Let us assume, that:
Let us assume, that:
x is the number of
small bottles (0,5l) of
mineral water “Vytautas”
y is the number of
small bottles (0,5l) of
mineral water “Rasa”
t is the number of large
bottles (1,5l) of mineral
water “Tiche”
z is the number of large
bottles (1,5l) of mineral
water “Vytautas”
Make an equation
system:
Make an equation
system:
x + y = 12
x=y+2
y + 2 + y = 12
2y = 12 – 2
2y = 10
/ ÷2
y=5
x=5+2=7
t + z = 24
t = 3z
3z + z = 24
4z = 24
/ ÷4
z=6
t = 3 · 6 = 18
2.
Count the praise:
5 · 1,39 + 7 · 1,49 + 6 · 2,29 + 18 · 2,09 = 68,74
The answer: 68,74 Litas
3.
Convert to Euros:
68,74 ÷ 3,4528 ≈ 19,9
Convert to Zlotys:
68,74 ÷ 0,81765 ≈ 84,07
Conclusion
Mineral water is underwater which contains
minerals and has curative features;
1 litre of mineral water should contain not less
than 1gr of minerals;
The composition of salts in mineral water should
be constant (stable);
Ionic composition of mineral water and the
concentration of ions are indicated on the bottle
sticker (label).